1.2+16.5x+4.905x^2=48

Solution for 1.2+16.5x+4.905x^2=48 equation:

1.2+16.5x+4.905x^2=48

We move all terms to the left:

1.2+16.5x+4.905x^2-(48)=0

We add all the numbers together, and all the variables

4.905x^2+16.5x-46.8=0

a = 4.905; b = 16.5; c = -46.8;
Δ = b2-4ac
Δ = 16.52-4·4.905·(-46.8)
Δ = 1190.466
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16.5)-\sqrt{1190.466}}{2*4.905}=\frac{-16.5-\sqrt{1190.466}}{9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16.5)+\sqrt{1190.466}}{2*4.905}=\frac{-16.5+\sqrt{1190.466}}{9.81}
$